2(x+1)=4[x-(3-x)]

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Solution for 2(x+1)=4[x-(3-x)] equation:


Simplifying
2(x + 1) = 4[x + -1(3 + -1x)]

Reorder the terms:
2(1 + x) = 4[x + -1(3 + -1x)]
(1 * 2 + x * 2) = 4[x + -1(3 + -1x)]
(2 + 2x) = 4[x + -1(3 + -1x)]
2 + 2x = 4[x + (3 * -1 + -1x * -1)]
2 + 2x = 4[x + (-3 + 1x)]

Reorder the terms:
2 + 2x = 4[-3 + x + 1x]

Combine like terms: x + 1x = 2x
2 + 2x = 4[-3 + 2x]
2 + 2x = [-3 * 4 + 2x * 4]
2 + 2x = [-12 + 8x]

Solving
2 + 2x = -12 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
2 + 2x + -8x = -12 + 8x + -8x

Combine like terms: 2x + -8x = -6x
2 + -6x = -12 + 8x + -8x

Combine like terms: 8x + -8x = 0
2 + -6x = -12 + 0
2 + -6x = -12

Add '-2' to each side of the equation.
2 + -2 + -6x = -12 + -2

Combine like terms: 2 + -2 = 0
0 + -6x = -12 + -2
-6x = -12 + -2

Combine like terms: -12 + -2 = -14
-6x = -14

Divide each side by '-6'.
x = 2.333333333

Simplifying
x = 2.333333333

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